728x90 AdSpace

  • Latest News

    Friday, 11 October 2019

    Some Important Questions for CBSE Class 12 Physics

    Chapter 1 - Electric Charges and Fields

    Coulomb’s Law


    Coulomb’s law states that Force exerted between two point charges:

    • Is inversely proportional to the square of the distance between these charges and
    • Is directly proportional to the product of the magnitude of the two charges
    • Acts along the line joining the two point charges.

    Here ε0 = 8.854 x 10-12 C2 N-1 m-2is called permittivity of free space.

    Forces between multiple charges – Superposition principle


    As per the principle of superposition, the force on any charge due to a number of other charges is the vector sum of all the forces on that charge due to other charges, taken one at a time.


    Electric Dipole


    An electric dipole is a pair of equal and opposite point charges q and –q, separated by a distance of 2a.
    • Direction from –q to q is the direction of the dipole.
    • The mid-point of locations of –q and q is called the centre of the dipole.
    • The total charge of an electric dipole is zero but since the charges are separated by some distance the electric field does not cancel out.
    • The dipole moment is the mathematical product of the separation of the ends of a dipole and the magnitude of the charges (2a x q).
    • Some molecules like H2O, have permanent dipole moment as their charges do not coincide. These molecules are called polar molecules.
    • Permanent dipoles have a dipole moment irrespective of any external Electric field.

    Gauss’s Law


    According to Gauss’s law, the total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The total electric flux through a closed surface is zero if no charge is enclosed by the surface.
    • Gauss’s law is true for any closed surface, no matter what its shape or size.
    • The term q on the right side of Gauss’s law includes the sum of all charges enclosed by the surface. The charges may be located anywhere inside the surface.
    • In the situation when the surface is so chosen that there are some changes inside and some outside, the electric field [whose flux appears on the left side of Eq. (1.31)] is due to all the charges, both inside and outside S. The term q on the right side of Gauss’s law, however, represents only the total charge inside S.
    • The surface that we choose for the application of Gauss’s law is called the Gaussian surface. The Gaussian surface can pass through a continuous charge distribution.
    • Gauss’s law is useful for the calculation of the electrostatic field for the asymmetric system.
    • Gauss’s law is based on the inverse square dependence on distance contained in the Coulomb’s law. Any violation of Gauss’s law will indicate a departure from the inverse square law.


    Applications of Gauss’s Law


    Field due to infinitely long straight uniformly charged wire

    Field due to a uniformly charged infinitely plane sheet



    Field due to a uniformly charged thin spherical shell


    Electric Field Lines

    Electric field lines are a pictorial way of representing electric field around a configuration of charges.

    • An electric field line is a curve drawn in such a way that the tangent to it at each point is in direction of the net field at that point.
    • The electric field is inversely proportional to the square of the distance; hence electric field near the charge is high and keeps on decreasing as we go farther from the charge. The electric field lines, however, remain constant but are very far apart (at higher distances) as compared to a lesser distance.


    Chapter 2 - Electrostatic Potential and Capacitance.


    Equipotential Surfaces


    An equipotential surface is one where the potential is the same at every point on the surface. For a single charge,
    • Since r is constant, the equipotential surfaces are concentric spherical surfaces centred at the charge.
    • Electric field lines are radial starting from or ending at the charge for positive and negative charges respectively.

    For any charge configuration, equipotential surface through a point is normal to the electric field at that point.




    Electrostatic Potential due to an Electric Dipole


    An electric dipole is an arrangement of two equal and opposite charges separated by a distance 2a. The dipole moment is represented by p which is a vector quantity.
    • The potential due to a dipole depends on r (distance between the point where potential is calculated and the mid-point of the dipole) and the angle between position vector r and dipole moment p.
    • Dipole potential is inversely proportional to square of r.


    Chapter 3 - Current Electricity

    VAN DE GRAAFF Generator


    Van de Graaff generator is used to generate high voltages of the order of a few million volts. This results in the generation of large electric fields for experimental purposes.

    Principle



    • The inner sphere has a higher potential than the outer if the charge q is positive.
    • If the two spheres are connected through a wire, the charge will flow from high to low potential.
    • Thus, providing smaller potentials at the inner sphere will keep building large amount of charge at the outer sphere, till the breakdown field of air (3 x 106 V/m) is reached.
    • This accumulates close to millions of volts.

    Construction


    • A large spherical conducting shell (of few metre radius) is supported at a height several meters above the ground on an insulating column.
    • A long narrow endless belt insulating material, like rubber or silk, is wound around two pulleys – one at ground level, one at the centre of the shell.
    • This belt is kept continuously moving by a motor driving the lower pulley.
    • It continuously carries a positive charge, sprayed on to it by a brush at ground level, to the top.
    • There it transfers its positive charge to another conducting brush connected to the large shell.
    • Thus positive charge is transferred to the shell, where it spreads out uniformly on the outer surface and a voltage difference of as much as 6 or 8 million volts (with respect to ground) can be built up.

    Energy stored in a Capacitor


    Energy is stored in the capacitor when work is done to move a positive charge from the negative conductor towards the positive conductor against the repulsive force.


    Effect of dielectric on Capacitance


    When a dielectric is present between the plates of a parallel plate capacitor fully occupying the region, the dielectric is polarized by the electric field. The surface charge densities are considered as σp and -σp.

    The dielectric constant of a substance is the factor by which the capacitance increases from its vacuum value when the dielectric is fully inserted in between the plates of the capacitor.



    Wheatstone bridge


    • Wheatstone bridge is a special arrangement of resistors as shown in the figure.
    • There are 4 resistances R1, R2, R3, and R4 arranged in such a manner that there is a galvanometer placed between the points B and D.
    • The arm BD is known as galvanometer arm. AC is known as battery arm.
    • And the circuit is connected to the battery across the pair of diagonally opposite points A and C.
    • According to the Wheatstone bridge principle:-
      • If (R1/R2)=(R3/R4), then Bridge is said to be balanced.
      • If the bridge is balanced there is no current flowing through the galvanometer arm.

    Mathematically:-
    • Assume current across the galvanometer arm Ig =0;
    • To prove:-(R1/R2) = (R3/R4)
    • Applying loop law to the loop ABDA,
    • There is no Emf, therefore,
    • 0= I1R1 - (I-I1)R3 + IgRG equation (i) where R= resistance of the galvanometer.
    • Applying loop Law to the loop BCDB,
    • No Emf, 0 = (I1-Ig)R2 – (I-I1+Ig)R4 + IgRequation(ii)
    • Putting I= 0 in equation(i) and (ii)
    • I1R1 - (I-I1) R3 = 0 => I1R1 = (I-I1) R3   equation (iii)
    • I1R2 – (I-I1)R4 = 0 => I1R2 = (I-I1) equation(iv)
    • Dividing equation(iii) with (iv)
    • (R1/R2) =(R3/R4) Hence proved.





    • Blogger Comments
    • Facebook Comments

    0 comments:

    Post a Comment

    Item Reviewed: Some Important Questions for CBSE Class 12 Physics Rating: 5 Reviewed By: Unknown
    Scroll to Top